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कृपया अपनी पसंदीदा भाषा चुनें
यदि $\alpha$ समीकरण $x^{2}+x+1=0$ को संतुष्ट करता है और $(1+\alpha)^{7}=A+B \alpha+C^{2}, A, B, C \geq 0$, तो
$5(3 A-2 B-C)$ के बराबर है
$x^{2}+x+1=0 \Rightarrow x=\omega, \omega^{2}=\omega$
मान लीजिए $\alpha=\omega$
अब $(1+\alpha)^{7}=-\omega^{14}=-\omega^{2}=1+\omega^{2}$
$A=1, B=1, C=0$
$\therefore 5(3 A-2 B-C)=5(3 A-2 B-C)=5(3 A-2 B-C)$
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