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कृपया अपनी पसंदीदा भाषा चुनें
यदि $\frac{{ }^{11} C _1}{2}+\frac{{ }^{11} C _2}{3}+\ldots+\frac{{ }^{11} C _9}{10}=\frac{n}{m}$ जहाँ $\operatorname{gcd}(n, m)=1$, तो $n+m$ किसके बराबर है?
$\sum _{r=1}^{9} \frac{{ }^{11} C _r}{r+1}$
$=\frac{1}{12} \sum _{r=1}^{9}{ }^{12} C _{r+1}$
$=\frac{1}{12}\left[2^{12}-26\right]=\frac{2035}{6}$
$\therefore m+n=2041$
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