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कृपया अपनी पसंदीदा भाषा चुनें
$99.9 \%$ पूर्ण होने में प्रथम कोटि अभिक्रिया के लिए आवश्यक समय $t _{1 / 2}$ (अर्धायु काल) के _________ गुना होता है।
$\frac{t _{99.9 \%}}{t _{1 / 2}}=\frac{\frac{2.303}{k}\left(\frac{a}{a-x}\right)}{\frac{2.303}{k} \log 2}=\frac{\log \left(\frac{100}{100-99.9}\right)}{\log 2}=\frac{\log 10^{3}}{\log 2}=\frac{3}{0.3}=10$
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