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कृपया अपनी पसंदीदा भाषा चुनें
यदि दो सदिश $\vec{P}=\hat{i}+2 m \hat{j}+m \hat{k}$ और $\vec{Q}=4 \hat{i}-2 \hat{j}+m \hat{k}$ एक दूसरे के लंबवत हैं। तो, $m$ का मान होगा :
(1) 1
(2) -1
(3) -3
(4) 2
$\overrightarrow{{}P} \cdot \overrightarrow{{}Q}=0$
$(\hat{i}+2 m \hat{j}+m \hat{k}) \cdot(4 \hat{i}-2 \hat{j}+m \hat{k})=0$
$\Rightarrow 4-4 m+m^{2}=0$
$\Rightarrow(m-2)^{2}=0 \Rightarrow m=2$
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