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कृपया अपनी पसंदीदा भाषा चुनें
$$(2 x+\frac{1}{x^{7}}+3 x^{2})^{5}$$ के विस्तार में स्थिर पद है
सामान्य पद है $\sum \frac{5 !(2 x)^{n_1}(x^{-7})^{n_2}(3 x^{2})^{n_3}}{n_1 ! n_2 ! n_3 !}$
स्थिर पद के लिए,
$n_1+2 n_3=7 n_2$
$n_1+n_2+n_3=5$
केवल संभावना $n_1=1, n_2=1, n_3=3$
$\Rightarrow$ स्थिर पद $=1080$
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